Question

2x-3/x(3x-6). 1-3x/x-2

Answer 1

$\frac{2x-3}{x(3x-6)}* \frac{1-3x}{x-2} = \frac{(2x-3)(1-3x)}{x(3x-6)(x-2)} = \frac{2x-6x^2-3+9x}{(3x^2-6x)(x-2)}= \frac{2x-6x^2-3+9x}{3x^3-6x^2+3x^3-6x^2}= \\ \\ = \frac{-6x^2+11x-3}{6x^3-12x^2} = \frac{-6x^2+11x-3}{6x^2(x-2)}$