Question

-6ab÷2ab×(-3a)cual es el procedimiento​

Answer 1

$\bf{-6ab\div2ab\times(-3a)$

$-\frac{6\times-3}{2}aaabb$

$-\frac{-18}{2}aaabb$

$-(-\frac{18}{2})aaabb$

$-(-9)aaabb$

$aaabb\times-(-9)$

$a^{3}b^{2} \times-(-9)$

$a^{3}b^{2} \times9$

$\boxed{\bf{9a^{3}b^{2} }}$  ←$\bf{Resultado$