Question

25(x+2)^2=(x-7)^2-81
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Answer 1

25(x+2)²=(x-7)²-81
25[x²+4x+4]=[x²-14x+49]-81
25x²+100x+100-x²+14x+32=0
24x²+114x+132=0
x²+4,75x+5.5=0
x=[(-4,75)+√(4,75)²-4(5.5)]/2⇔x=-2

o

x=[(-4,75)-√(4,75)²-4(5.5)]/2⇒x=-11/4