Question

7x – 8 = x ^ 2 ayuda por favor

Answer 1

Respuesta:

$7x-8-x^{2} = 0\\-x^{2} +7x-8=0\\x^{2} -7x+8=0\\x=\frac{-(-7)+-\sqrt{(-7^{2} )-4 * 1 * 8} }{2 * 1} \\x=\frac{7+-\sqrt{49-32} }{2} \\\\x= \frac{7+\sqrt{17} }{2} \\x= \frac{7-\sqrt{17} }{2} \\x_{1} =\frac{7-\sqrt{17} }{2} , x_{2} =\frac{7+\sqrt{17} }{2}$