Question

3z²-(z-5)(z-3)=3z²+1​

Answer 1

Respuesta:

Distribuye

2−1(−5)(−3)=32+1

2−(−3)+5(−3)=32+1

Answer 2

R3z²-(z-5)(z-3)= 3z²+1

3z²-(z²-8z+15)= 3z²+1

3z²-z²+8z-15= 3z²+1

-z²+8z= 1+15

z²-8z= -1-15

z(z-8)= -16

z= 16/(z-8)