Question

ayudame porfavor


√225/49
∛-125
4√7-8√7+√7
2/3√3-4/5√3+7/2√3-3√3

Answer 1

∛-125
4√7-8√7+√7
2/3√3-4/5√3+7/2√3-3√3

$\sqrt{ \frac{225}{49} } = \sqrt{ \frac{5 ^{2}*3 ^{2} }{7 ^{2} } } = \frac{5*3}{7} = \frac{15}{7} = 2,14$

$\sqrt[3]{-125} = \sqrt[3]{-5 ^{3} } = -5$

$4 \sqrt{7} -8 \sqrt{7} + \sqrt{7} = 5 \sqrt{7}$      4 - 8 +1 = 5

$\frac{2}{3} \sqrt{3} - \frac{4}{5} \sqrt{3} + \frac{7}{2} \sqrt{3} -3 \sqrt{3} =$

$\frac{2}{3} - \frac{4}{5} + \frac{7}{2} -3 = \frac{(2*10)-(6*4)+(15*7)-(3*30)}{30} =$

$\frac{20-24+105-90}{30} = \frac{11}{30}$

= $\frac{11}{30} \sqrt{3}$