Question

Determina la masa molar de los siguientes compuestos, con procedimiento:

a) KMnO4
b) (NH4)3PO4​​

Answer 1

Respuesta:

KMnO5 = 158.03 g/mol

(NH4)3PO4 = 149.08 g/mol

Explicación:

Inciso A

K = 39.0983 * 1 = 39.0983 g/mol

Mn = 54.9380 *1  = 54.9380 g/mol

O = 15.9994 * 4 = 63.9976 g/mol

39.0983 + 54.9380 + 63.9976 = 158.0339 g/mol

Inciso B

N = 14.0067 * 1 = 14.0067 g/mol

H = 1.00784 * 4 = 4.03136 g/mol

(14.0067 + 4.03136 ) * 43= 54.11418 g/mol

P = 30.9737 =* 1 = 30.9737 g/mol

O = 15.9994 * 4 = 63.9976 g/mol

30.9737 + 63.9976 = 94.9713 g/mol

54.11418 + 94.9713 = 149.08548 g/mol