Question

E1; 2x-y=1
E2; 4x+3y=27

hacerlo con el sistema de reducción o sustitución pls

Answer 1

MÉTODO DE SUSTITUCIÓN

2x - y = 1

4x + 3y = 27

x1 = 1 + y/2

4 (1 + y/2) + 3y = 27

4 (1 + y) = 2 (27 - 3y)

4 + 4y = 54 - 6y

6y + 4y = 54 - 4

10y = 50

y = 50/10

y = 5

2x - y = 1

2x - 5 = 1

2x = 1 + 5

2x = 6

x = 6/2

x = 3

4x + 3y = 27

4x + 3 (5) = 27

4x + 15 = 27

4x = 27 - 15

4x = 12

x = 12/4

x = 3

MÉTODO DE REDUCCIÓN

2x - y = 1

2x - y = 14x + 3y = 27

2x - y = 1 (-2)

4x + 3y = 27

-4x + 2y = -2

4x + 3y = 27

___________

// + 5y = 25

y = 25/5

y = 5

2x - y = 1

2x - 5 = 1

2x = 1 + 5

2x = 6

x = 6/2

x = 3

4x + 3y = 27

4x + 3 (5) = 27

4x + 15 = 27

4x = 27 - 15

4x = 12

x = 12/4

x = 3

R// x = 3; y = 5