Question

calcular la composicion de porcental o centesimal e la siguientes sustancias C2H6O , C3H8O3 , C4H10O

Answer 1

Mm C2H6O
C:  2 x 12 = 24 g/mol
H: 6 x 1 = 6 g/mol
O:1 X 16 = 16 g/mol
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       Mm = 46 g/mol

C: 46 g -------100 %
     24 g -------  x
x = 52.69 % C


H: 46 g -------100 %
     6 g -------  x
x = 13.04 % H

O: 46 g -------100 %
     16 g -------  x
x = 34.78 % O

2.
C3H8O3
C: 3 x 12 = 36 g/mol
H: 8 x 1 = 8 g/mol
O:3 X 16 = 48 g/mol
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       Mm = 92 g/mol

C: 92 g -------100 %
      36 g -------  x
x = 39.13 % C

H: 92 g -------100 %
      8 g -------  x
x = 8069 % H

O: 92 g -------100 %
     48 g -------  x
x = 52.17 % O

3.
C4H10O

C: 4 x 12 = 48 g/mol
H: 10 x 1 = 10 g/mol
O:1 X 16 = 16 g/mol
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       Mm = 74 g/mol

C: 74g ----- 100%
    48 g -----    x

x = 64.86 % C

H: 74g ----- 100%
    10 g -----    x

x =13.51 % H

O: 74g ----- 100%
    16 g -----    x

x =21.62 % O