Question

63 puntos ayudemne porfas :
1) 4(x-10)=-6(2-x)-6x
2) 2(x+1)-3(x-2)=x+6

Answer 1

4(x-10)=-6(2-x)-6x
4x - 40 = -12 + 6x - 6x
4x -40 = -12
4x = -12+40
4x = 28
$x = \frac{28}{4}$
x = 7


2(x+1)-3(x-2)=x+6
2x + 2 - 3x + 6 = x+6
-x + 8 = x + 6
8-6 = x+x
2 =  2x
$\frac{2}{2} = x$
1 = x 

Answer 2

$1)4(x-10)=-6(2-x)-6x\\ 4x-40=-12+6x-6x\\ 4x=-12+40\\ 4x=28\\ x=28:4\\ x=7\\\\ 2) 2(x+1)-3(x-2)=x+6\\ 2x+2-3x+6=x+6\\ 2x-3x-x=-2-6+6\\ -2x=-2\\ x=-2:(-2)\\ x=1$