Question

Ayudenmen A Sacar EL Resultado De Los Productosss


(x²+3x-2)x²

xy(x²-xy+y²)x

-x²y³(4-3xy²+2x²y³)

1/3x³(6-3x³y+9x²y³(

(2x³).(5x³)

2(12x³).(4x)

35.(2x²y³z)

4(5x²y³z).(2y²z²)

(18x3³y²Z⁵).(6x³yz)

(-2x³).(-5x).(-3x²)

2xⁿ(xⁿ-2xⁿ⁺¹)

Answer 1

(x²+3x-2)x²  =   $x^{4}+3 x^{3} -2 x^{2}$

xy(x²-xy+y²)x = $x^{4}y - x^{3}y+ x^{2} y^{2}$

-x²y³(4-3xy²+2x²y³) =$-4 x^{2} y^{3} + 3 x^{3} y^{5}-2 x^{4} y^{6} }$

(2x³).(5x³)=$10 x^{6}$

2(12x³).(4x)=$96 x^{4}$

35.(2x²y³z) = $70 x^{2} y^{3} z$

4(5x²y³z).(2y²z²) = $40 x^{2} y^{5} z^{3}$

Answer 2

Respuesta:

Explicación paso a paso:

lo siento es 1x4z43y