Question

ayuda necesito esto urgente

Answer 1

Explicación paso a paso:

T. pitágoras

${ \sqrt{15} }^{2} = { \sqrt{10} }^{2} + {c}^{2} \\ 15 = 10 + {c}^{2} \\ \sqrt{5} = c$

$\sin( \alpha ) = \frac{ \sqrt{10} }{ \sqrt{15} } = \frac{ \sqrt{6} }{3} \\ \cos( \beta ) = \frac{ \sqrt{5} }{ \sqrt{15} } = \frac{ \sqrt{3} }{3} \\ \tan( \alpha ) =$

tan a = /10 ÷ /5 = /2

csc a = /15 ÷ /10 = /6 ÷ 2

ctg b = /5 ÷ /10 = /2 ÷ 2