Question

hallar la composición porcentual del siguiente compuesto CO2

Answer 1

Respuesta:

Mm CO

C: 1 x 12 = 12 g/mol

O: 1 x 16 = 16 g/mol

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          Mm = 28 g/mol

C: 28 g  ----- 100 %

    12 g -----  x

      x = 42.86 %

O: 28 g --- 100 %

    16 g ---  x

      x = 57.14 %

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CO2

Mm

C: 1 x 12 = 12 g/mol

O: 2 x 16 = 32 g/mol

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          Mm = 44 g/mol

C: 44 g ---------- 100 %

    12 g ---------    x

        x = 27.27 %

O:    44 g ---------- 100 %

       32 g ---------    x

        x = 72.72 %

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Explicación:

NO TIENE IGUAL COMPOSICION PORCENTUAL

Espero haberte ayudado saludos K.S.C.