Question

Despejar [Y] de
√XY+2=RL

Answer 1

Respuesta:

DESPEJAR "Y"

$\sqrt{xy} +2= RL\\\\(\sqrt{xy})^{2} = (RL-2)^{2} \\\\xy=(RL)^{2} - 4RL+4\\\\Y=\frac{R^{2} L^{2} - 4RL+4}{X}$