Respuestas
Sistema de ecuación
Método de sustitución
5x - 2y = 1 (Ec1)
2x + 3y = 27 (Ec2)
x1 = 1 + 2y/5
2x + 3y = 27 (Ec2)
2 (1 + 2y/5) + 3y = 27
2 (1 + 2y) = 5 (27 - 3y)
2 + 4y = 135 - 15y
4y + 15y = 135 - 2
19y = 133
y = 133/19
y = 7
5x - 2y = 1 (Ec1)
5x - 2 (7) = 1
5x - 14 = 1
5x = 14 + 1
5x = 15
x = 15/5
x = 3
2x + 3y = 27 (Ec2)
2x + 3 (7) = 27
2x + 21 = 27
2x = 27 - 21
2x = 6
x = 6/2
x = 3
R// x = 3; y = 7
Comprobación
5x - 2y = 1 (Ec1)
5 (3) - 2 (7) = 1
15 - 14 = 1
1 = 1
2x + 3y = 27 (Ec2)
2 (3) + 3 (7) = 27
6 + 21 = 27
27 = 27
Espero haberte ayudado. Suerte en los estudios ʕ•́ᴥ•̀ʔっ♡.