Question

(4x²–5x+4) + (2x²–5x+1)​

Answer 1

(4x²–5x+4) + (2x²–5x+1)​

4x²–5x+4 + 2x²–5x+1​

4x² + 2x² –5x –5x + 4+1​

6x² - 10x + 5

Eternamente axllxa

Answer 2

Respuesta:

$(4 { \times }^{2} - 5 \times + 4) \\ + (2 { \times }^{2} - 5 \times + 1) \\ \\ solucion = 6 { \times }^{2} - 10 \times + 5$