• Asignatura: Matemáticas
  • Autor: isamartinezcollazos3
  • hace 4 años

2–3 + (–4) =
2. 4–2– (–3) – (–1) =
3. 5· (–12 + 4) =
4. –4· (–3)· (–3) =
5. –(–3)· (–3) =
6. 4· (4–2) =
7. –5· (–12+4) =
8. –4· (–2–3) – 1=
9. –1· (–2)+( –2)· ( –3)· (–1) =
10. 4 – 20:(–5) =
11. 25:(–5) – 1=
12. –3·(–2)·(–1) – 6:3 =
13. –10 – (–2)·(–1)·(–3) =
14. –3·(–4 +(–2)) =
15. 63:(4+5) –4·(5–3) =
16. – 2· (3 – 6) – 16:(6 – 10) =
17. 2·(– 4 + 1) + (8 – 1):7 =
18. –10·(– 1– 5) – (–5 – 3):(–2) =
19. 7·[6 –(–5)] – 4·(5 – 3) =
20. 10·[3–2·(5–4) –2·(4–2)]
. –3·{–6[2·(–3 – 4·(–5+4) – 2 + 3) – 7 – 7] + 4 – 3} =
. {–34:[3·(–3 – 50:(–6 – 4) –12 + 3) – 7 + 11] + 5 – 1}:6

Respuestas

Respuesta dada por: LadyErazo
4

Explicación paso a paso:

2–3 + (–4) =No se si va el 2 pero si va es(-5) y si empieza desde -3 +(-4)= -7

2. 4–2– (–3) – (–1) =6

3. 5· (–12 + 4) = -40

4. –4· (–3)· (–3) = -36

5. –(–3)· (–3) = -9

6. 4· (4–2) = 8

7. –5· (–12+4) = 40

8. –4· (–2–3) – 1= 19

9. –1· (–2)+( –2)· ( –3)· (–1) = -4

4 -  \frac{20}{ - 5}  = 8

10. 4 – 20:(–5) =8

11. 25:(–5) – 1=

\frac{25}{ - 5}  - 1 =  - 6

12. –3·(–2)·(–1) – 6:3 =

 - 3( - 2)( - 1) -  \frac{6}{3}  =  - 8

13. –10 – (–2)·(–1)·(–3) = -4

14. –3·(–4 +(–2)) = 18

15. 63:(4+5) –4·(5–3) =

 \frac{63}{(4 + 5)}  - 4(5 - 3) =  - 1

16. – 2· (3 – 6) – 16:(6 – 10) =

 - 2(3 - 6) -  \frac{16}{(6 - 10)}  = 10

17. 2·(– 4 + 1) + (8 – 1):7 =

( - 4 + 1) +  \frac{(8 - 1)}{7}  =  - 2

18. –10·(– 1– 5) – (–5 – 3):(–2) =

 - 10( - 1 - 5) -  \frac{( - 5 - 3)}{ - 2}  = 56

19. 7·[6 –(–5)] – 4·(5 – 3) =

7(6 - ( - 5)) - 4(5 - 3) = 69

20. 10·[3–2·(5–4) –2·(4–2)]

10(3 - 2(5 - 4) - 2(4 - 2)) =  - 30

. –3·{–6[2·(–3 – 4·(–5+4) – 2 + 3) – 7 – 7] + 4 – 3} =

 - 3( - 6(2( - 3 - 4( - 5 + 4) - 2 + 3) - 7 - 7) + 4 - 3) = 33

. {–34:[3·(–3 – 50:(–6 – 4) –12 + 3) – 7 + 11] + 5 – 1}:6

 \frac{ - 34}{ \frac{3( - 3 - 50)}{(( - 6 - 4) - 12 + 3) - 7 + 11} }   +  \frac{(5 - 1)}{6}  =   - \frac{404}{159}

bueno la última es asta donde más comprendo ,estaba muy confusa, espero ayudarte


isamartinezcollazos3: me puedes mandar las soluciones
isamartinezcollazos3: por fa
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