Question

log2(u) = 14 (3log2(a) – (5log2(b) + 2log2(c))).
Ayudaaaaa !!

Answer 1

Respuesta:

Explicación paso a paso:

log2(u) = 1/4 (3log2(a) – (5log2(b) + 2log2(c))).

$\log_{2}(u) = \frac{1}{4} (3\log_{2}(a) - 5\log_{2}(b) + 2\log_{2}(c))$

$\log_{2}(u) = \frac{3}{4} \log_{2}(a) -\frac{5}{4} \log_{2}(b) + \frac{2}{4} \log_{2}(c)$

$4\log_{2}(u) = 3\log_{2}(a) -5\log_{2}(b) + 2\log_{2}(c)$

$\log_{2}(u^{4} ) = \log_{2}(a^3) -\log_{2}(b^5) + \log_{2}(c^2)$

$\log_{2}(u^{4} ) = \log_{2}(\frac{a^3 c^2}{b^5} )$

$u^{4} = \frac{a^3 c^2}{b^5}$

LIKE, 5 ESTRELLAS Y CORONITA XD.