Question

25x²+20x+2=0
cuál es su solución?​

Answer 1

Respuesta:

= − 2 4 5

Explicación paso a paso:

Answer 2

Respuesta:

$\boxed{\mathsf{x_{1}=-\frac{2}{5}+\frac{\sqrt{2}}{5}\,\,,x_{2}=-\fracc{2}{5}-\frac{\sqrt{2}}{5}}}$

Explicación paso a paso:

$\mathsf{25x^{2}+20x+2=0}\,\,\textsf{Aplicando la f\'ormula general,con a=25,b=20 y c=2,nos queda:}\\\\x=\frac{-20\pm\sqrt{(20)^{2}-4(25)(2)}}{2(25)}\\\\x=\frac{-20\pm\sqrt{400-200}}{50}\\\\x=\frac{-20\pm\sqrt{200}}{50}\\\\x=\frac{-20\pm 10\sqrt{2}}{50}\\\\x_{1}=\frac{-20+10\sqrt{2}}{50}=-\frac{2}{5}+\frac{\sqrt{2}}{5}\\\\x_{2}=-\frac{2}{5}-\frac{\sqrt{2}}{5}$