Question

aplicar propiedad distributiva y verificar
3(x+2)+2(x+1)=13

Answer 1

3x+6+2x+2=13
5x+8=13
5x=5
x=5/5
x=1


Verificar:

3(1+2)+2(1+1)=13
3(3)+2(2)=13
9+4=13
13=13

listo!!!

Answer 2

3 (x + 2) + 2 (x + 1) = 13

3x + 6 + 2x + 2 = 13

3x + 2x + 6 + 2 = 13

5x + 8 = 13

5x = 13 - 8

5x = 5

x = 5/5

x = 1

Solución : 

x = 1

COMPROBAMOS : 

3 (x + 2) + 2 (x + 1) = 13

3 (1 + 2) + 2 (1 + 1) = 13

3 (3) + 2 (2) = 13

9 + 4 = 13

13 = 13

Listo. La solución es correcta.