Question

utiliza las propiedades de la potenciación para:

Answer 1

C)

(√8)^5 = (√2³)^5 = (2^(3/2))^5 = 2^(15/2) = √2^15

( - 5)^4 = 625

( - 1/2)^( - 1) = - 2

(√π)^( - 2) = (1/√π)² = (√π /π)² = π/π² = 1/π

(√3/6)² = 3/36 = 1/12

(x^0 . y² . z^( - 1))^( - 2) . (x² . y^( - 2) . z)
(x^(0.-2) . y^(2.-2) . z^(-1.-2)) . (x² . y^( - 2) . z)
(x^0 . y^( - 4) . z²) . (x² . y^( - 2) . z)
 y^( - 4) . z² . x² . y^( - 2) . z
y^(-4-2) . z^(2+1) . x²
y^(-6) . z³ . x²
(z³ . x²)/y^6

(5/√2)³ = (5√2/2)³ = 125³√2/8

(3/4)³ = 27/64

(1/√2)^( - 2) = (√2/2)^( - 2) = (2/√2)² = 4/2 = 2

P)

(√7)^7/(√7)^5 = 7^(7/2)/7^(5/2) = 7^(7/2 - 5/2) = 7^(2/2) = 7

(7x)³ / (49x²) = 7³x³/7²x² = 7x