Question

Si: sen(x+10º) =cos(x+40º)
halle: E=tg3x+4(√3) sen (x+10º)

Answer 1

 x+10 + x+40 = 90
2x = 40
x =20

E= tg(60) + 4($\sqrt{3}$). sen(30)
  = $\sqrt{3}$+  4($\sqrt{3}$) . $\frac{1}{2}$
  = $\sqrt{3} + 2 \sqrt{3}$
  =3$\sqrt{3}$