Question

\frac{1}{(x-1)²} - \frac{3}{2x-2}=-\frac{3}{2x+2}


ayuda :')

no se que xhxh termine escribiendo xD

Answer 1

$\bf{\frac{1}{(x-1)^{2} } - \frac{3}{2x-2}= -\frac{3}{2x+2}}$

$\frac{1}{(x-1)^{2} } - \frac{3}{2(x-1)}= -\frac{3}{2x+2}$

$\frac{1}{(x-1)^{2} } - \frac{3}{2(x-1)}= -\frac{3}{2(x+1)}$

$\frac{2(x+1)}{x-1} - 3(x+1)=-3(x-1)$

$\frac{2(x+1)}{x-1} - 3x-3=-3x+3$

$\frac{2(x+1)}{x-1} - 3=3$

$2(x+1)-3(x-1)=3(x-1)$

$5-x=3x-3$

$5=3x-3+x$

$5=4x-3$

$5+3=4x$

$8=4x$

$\frac{8}{4} = x$

$2 = x$

$\bf{Respuesta:$

$\boxed{\bf{x=2}}$