Question

4x²+7x+3=0 fórmula general​

Answer 1

Respuesta:

0

Explicación paso a paso:

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Answer 2

$4x^2+7x+3=0$

$\mathrm{formula \: general}$

$\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\\\ \mathrm{Para}\quad a=4,\:b=7,\:c=3$

$x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\cdot \:4\cdot \:3}}{2\cdot \:4}$

$x_{1,\:2}=\frac{-7\pm \sqrt{7^2-48}}{2\cdot \:4}$

$x_{1,\:2}=\frac{-7\pm \sqrt{49-48}}{2\cdot \:4}$

$x_{1,\:2}=\frac{-7\pm \sqrt{1}}{2\cdot \:4}$

$x_{1,\:2}=\frac{-7\pm 1}{2\cdot \:4}$

$\rightarrow x_{1}=\frac{-7+ 1}{2\cdot \:4}$

    $x_{1}=\frac{-7+ 1}{8}$

    $x_{1}=\frac{-6}{8}$

    $x_{1}=\frac{-3}{4} \longrightarrow primera \: solucion$

$\rightarrow x_{2}=\frac{-7- 1}{2\cdot \:4}$

    $x_{2}=\frac{-7- 1}{8}$

    $x_{2}=\frac{-8}{8}$

    $x_{2}= -1 \longrightarrow segunda \: solucion$