Question

14x^2-13x-12=0 x fas con proceso

Answer 1

14x² - 13x - 12 = 0  

x₁ = - (- 13) + √((13)² - 4 * 14 (- 12)) 2 * 14

x₁ = - (- 13) + √(169 - 56 (- 12))/28

x₁ = 13 + √(169 + 672)/28

x₁ = 13 + √(841)/28

x₁ = (13 + 29)/28

x₁ = 42/28----simplificamos

x₁ = 3/2
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x₂ = (13 - 29)/28

x₂ = - 16/28--simplificamos

x₂ = - 4/7

Solución : 

x₁ = 3/2
x₂ = - 4/7