Question

AYUDAAA PORFAVOOOOORRR!!!
2(x-4)^2-(x+3)^2=(x-1)(x+3)

Answer 1

Respuesta:

$2\left(x-4\right)^2-\left(x+3\right)^2=\left(x-1\right)\left(x+3\right)\quad :\quad x=\frac{13}{12}$

Explicación paso a paso:

$2\left(x-4\right)^2-\left(x+3\right)^2=\left(x-1\right)\left(x+3\right)$

Desarrolla : $2\left(x-4\right)^2-\left(x+3\right)^2 = x^2-22x+23$

Desarrolla : $\left(x-1\right)\left(x+3\right) =x^2+2x-3$

$x^2-22x-\left(x^2+2x\right)=x^2+2x-26-\left(x^2+2x\right) = \frac{-24x}{-24}=\frac{-26}{-24}$

$x=\frac{13}{12}$