Question

calcular el termino de 5 progresiones geometricas que empiecen en 1/16 y la razon es 2

Answer 1

$a_{n } = a_{1} . r^{n-1}\\\\ a_{5 } = (\frac{1}{16} ) . 2^{5-1}\\\\a_{5 } = (\frac{1}{16} ) . 2^{4}\\\\a_{5 } = (\frac{1}{16} ) . 16\\\\a_{5 } = \frac{16}{16}\\\\a_{5 } = 1$

Eternamente axllxa