Question

x²+6x=0
X²+4=0
(2m+5n)²=
(3x-6y)²=
(3/4j-2/5k)²
X²+6x=40
X²-4x=21
Y²-9x=-20
Factorizacion ​

Answer 1

Respuesta:

x²+6x=0= x=0,−6

X²+4=0 = x=±2i

(2m+5n)²=$4m^{2}+20mn+25n^{2}$

(3x-6y)²=  $9(x-2y)^{2}$

(3/4j-2/5k)² = 9$j^{2}$/16 - 3jk/5 + 4$k^{2}$ /25

X²+6x=40 = x(x + 6)

X²-4x=21 = x= 7,-3

Y²-9x=-20= y= $\sqrt{11i}$

Explicación paso a paso:

espero te sirva uwu