Question

encontar el termino de progresiones geometricas 1,3,9,27,91,...,a10

Answer 1

$a_{n} = a_{1} . r^{n-1}\\\\a_{10} = 1 . (3)^{10-1}\\\\a_{10} = 1 . (3)^{9}\\\\a_{10} = 1 x 19 683\\\\a_{10} = 19 683$

Eternamente axllxa