Question

Me pueden ayudar a resolver mi guía urgente por favor

Answer 1

A.lim_x⇒4 (x-4)(x+3)/(x-4)*1 
  lim_x⇒4 (x+3)
(4+3)=7
B. lim_x⇒2 (4-x²)/(3-√x²+5)
lim_x⇒2 (4-x²)/ lim_x⇒2 (3-√x²+5)
(4-2²)/(3-√2²+5)
(-4+4)/(8-2)
0/6
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