Question

73 fahrenheit a kalvin​

Answer 1

73 °F − 32) × 5/9 + 273.15 = 295.928 K

Answer 2

73 Fahrenheit a Kelvin​

Solución

$K = \dfrac{5*(F-32)}{9} + 273.15$

$K = \dfrac{5*(73-32)}{9} + 273.15$

$K = \dfrac{5*41}{9} + 273.15$

$K = \dfrac{205}{9} + 273.15$

$\dfrac{9\:K}{\diagup\!\!\!\!9} = \dfrac{205}{\diagup\!\!\!\!9} + \dfrac{2458.35}{\diagup\!\!\!\!9}$

$9\:K = 205 + 2458.35$

$9\:K = 2663.35$

$K = \dfrac{2663.35}{9}$

$\boxed{\boxed{K \approx 295.928}}\:\:\:\:\:\:\bf\blue{\checkmark}$

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