Question

Ayudenmen los necesito para hoy ​

Answer 1

RESPUESTAS:

PRIMERA ACTIVIDAD

f(4) = (4)² – 4(4) – 5

f(4) = 16 – 16 – 5

f(4) = – 5

f(3) = (3)² – 4(3) – 5

f(3) = 9 – 12 – 5

f(3) = 9 – 12 – 5

f(3) = – 8

f(2) = (2)² – 4(2) – 5

f(2) = 4 – 8 – 5

f(2) = – 9

f(1) = (1)² – 4(1) – 5

f(1) = 1 – 4 – 5

f(1) = – 8

f(0) = (0)² – 4(0) – 5

f(0) = 0 – 0 – 5

f(0) = – 5

f(–1) = (–1)² – 4(–1) – 5

f(–1) = 1 + 4 – 5

f(–1) = 0

f(–2) = (–2)² – 4(–2) – 5

f(–2) = 4 + 8 – 5

f(–2) = 7

f(–3) = (–3)² – 4(–3) – 5

f(–3) = 9 + 12 – 5

f(–3) = 16

f(–4) = (–4)² – 4(–4) – 5

f(–4) = 16 + 16 – 5

f(–4) = 27

SEGUNDA ACTIVIDAD:

f(5) = 2(5)² + (5) – 6

f(5) = 2(25) + 5 – 6

f(5) = 50 + 5 – 6

f(5) = 49

f(4) = 2(4)² + (4) – 6

f(4) = 2(16) + 4 – 6

f(4) = 32 + 4 – 6

f(4) = 30

f(3) = 2(3)² + (3) – 6

f(3) = 2(9) + 3 – 6

f(3) = 18 + 3 – 6

f(3) = 15

f(2) = 2(2)² + (2) – 6

f(2) = 2(4) + 2 – 6

f(2) = 8 + 2 – 6

f(2) = 4

f(1) = 2(1)² + (1) – 6

f(1) = 2(1) + 1 – 6

f(1) = 2 + 1 – 6

f(1) = – 3

f(0) = 2(0)² + (0) – 6

f(0) = 2(0) + 0 – 6

f(0) = 0 + 0 – 6

f(0) = – 6

f(–1) = 2(–1)² + (–1) – 6

f(–1) = 2(1) –1 – 6

f(–1) = 2 –1 – 6

f(–1) = – 5

f(–2) = 2(–2)² + (–2) – 6

f(–2) = 2(4) –2 – 6

f(–2) = 8 –2 – 6

f(–2) = 0

f(–3) = 2(–3)² + (–3) – 6

f(–3) = 2(9) –3 – 6

f(–3) = 18 –3 – 6

f(–3) = 9

f(–4) = 2(–4)² + (–4) – 6

f(–4) = 2(16) –4 – 6

f(–4) = 32 –4 – 6

f(–4) = 22

f(–5) = 2(–5)² + (–5) – 6

f(–5) = 2(25) –5 – 6

f(–5) = 50 –5 – 6

f(–5) = 39