Respuestas
Respuesta:
(x+1)(y-1)
resupuesta
xy-x+y-1
A) (x+1) (y-1)=
= (x+1) [(y+(-1) ]
= x(y) + x(-1) +1(y) +1(-1)
= xy -x + 1y -1
R//= xy -x + 1y -1
B) (x-1) (y-1)=
= [x+(-1)] [y+(-1)]
= x(y) + x(-1) + (-1)(y) +(-1)(-1)
= xy -x -y + 1
R//= xy -x -y + 1
C) (2x+2) (-y+2)=
= (2x+2) [(-y) +2]
= 2x(-y) + 2x(2) + 2(-y) + 2(2)
= 2xy + 4x -2y +4
R//= 2xy + 4x -2 + 4
D) (-x-2) (2y -3)=
= [(-x)+2)] [2y+(-3)]
= (-x)(2y) + (-x)(-3) + (-2)(2) + (-2)(-3)
R//= -2yx + 3x -4y + 6
E) (xy-x) (y+10)=
= [xy+(-x)] (y+10)
= xy(y) +xy(-10) + (-x)(y) + (-x)(10)
R//= xy² + 10xy -xy -10x
F) (2xy-y) (5x-3)=
= [2xy(-y)] [5x(-3)]
= 2xy(5x) + 2x(-3) + (-y)(5x) + (-y)(-3)
R//=10x²y -6xy -5xy + 3y
Espero te sirva de ayuda <3