Question

En cada caso encuentra el valor de x. Con procedimientos.
A. 2x-3(x-2)-11=2
B. 1+6x+9=2(3x+3)-x
C. 6x+2-x=3+3x
D. 14x-2x-3(3x+1)+1=2

Answer 1

El D) es asi:
14x-2x-3 (3x+1)+1=2
14x-2x-9x-3+1=2
3x-1=2
3x=2+1
3x=3
x=3/3
x=1

Answer 2

2x - 3 (x - 2) - 11 = 2

2x - 3x + 6 - 11 = 2

- x - 5 = 2

- x = 2 + 5

- x = 7

x = - 7
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1 + 6x + 9 = 2 (3x + 3) - x

1 + 6x + 9 = 6x + 6 - x

10 + 6x = 5x + 6

6x - 5x = 6 - 10

x = - 4
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6x + 2 - x = 3 + 3x

5x + 2 = 3 + 3x

5x - 3x = 3 - 2

2x = 1

x = 1/2
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14x - 2x - 3 (3x + 1) + 1 = 2

14x - 2x - 9x - 3 + 1 = 2

14x - 11x - 2 = 2

3x = 2 + 2

3x = 4

x = 4/3

Listo.