Question

Ejercicio 128 resuelto del álgebra de Baldor numero 10 1/2a - 2+b/3ab - 5/6a2b3

Answer 1

1/2a - (2+b)/3ab - 5/6a²b³
(3ab - 4a + 2ab)/6a²b - 5/6a²b³
(ab - 4a)/6a²b - 5/6a²b³
a(b - 4)/a(6ab) - 5/6a²b³
(b - 4)/6ab - 5/6a²b³
(6a²b^4 - 24a²b³ - 30ab)/36a³b^4
6ab(ab³ - 4ab² - 5)/6ab(6a²b³)
(ab³ - 4ab² - 5)/6a²b³