Question

(x³-8y^9)² ayudaaaaaaaaaaáaaaaaa​

Answer 1

Usamos el ( a - b )² = a² - 2ab + b ²

$( {x}^{3} {)}^{2} - 2 {x}^{3} \times 8 {y}^{9} + (8 {y}^{9} {)}^{2}$

simplificamos multiplicando los exponentes

${x}^{6} - 2 {x}^{3} \times 8 {y}^{9} + (8 {y}^{9} {)}^{2}$

calculamos

${x}^{6} - 16 {x}^{3} {y}^{9} + (8 {y}^{9} {)}^{2}$

elevan el factor a la potencia

${x}^{6} - 16 {x}^{3} {y}^{9} + 64 {y}^{18}$