Question

ayúdenme a resolver estos ejercicios con el procedimiento es para hoy por favor

Answer 1

Respuesta:

${4}^{0} ( {3}^{ - 1} + {6}^{ - 1} ) = 1 \times ( \frac{1}{3} + \frac{1}{6} ) = 1 \times (\frac{2}{6} + \frac{1}{6} ) = 1 \times \frac{3}{6} = \frac{3}{6} = \frac{1}{2}$

${3}^{ - 2} + {5}^{0} = \frac{1}{ {3}^{2} } + 1 = \frac{1}{9} + 1 = \frac{1}{9} + \frac{9}{9} = \frac{10}{9}$

${( {5a}^{0} )}^{ - 2} = ({5 \times 1})^{ - 2} = {5}^{ - 2} = \frac{1}{ {5}^{2} } = \frac{1}{25}$