Question

(3x-4)(4x-3)=(6x-4)(2x-5)

Answer 1

Multiplica paréntesis:
12x^2-9x-16x+12=12x^2-8x-30x+20
12x^2-12x^2-9x-16x+8x+30x=20-12
13x=8
x=8/13

Answer 2

(3x-4)(4x-3)= 12x-9x-16x+12
                       -13x+12
(6x-4)(2x-5)= 12x-30x-8x+20
                         -26+20
(-13x+12)(-26+20)
39x-260x-312+240
39x-260x=-221
-312+240=-72