Question

ayuda pregunta seria gracias por favor ​

Answer 1

Respuesta:

a

$(2x - 5)^{2} \\ 2x - 5 = 0 \\ 2x = 5 \\ x = \frac{5}{2}$

b

$x(3x - 2) - (3x + 2)(3x - 2) \\ x(3x - 2) - 9{x}^{2} - 4 \\ 3 {x}^{2} - 2x - 9 {x}^{2} - 4 \\ - 6 {x}^{2} - 2 x- 4 \\ 6{x}^{2} + 2x - 4 \\ \frac{6{x}^{2} + 2x - 4}{2} \\ 2(3 {x}^{2} + x - 2) \\ 2(3x + 2)(x - 1) \\ (6x + 4) = 0 \\ 6x = - 4 \\ x = \frac{ - 4}{6} \\ x = - \frac{2}{3} \\ (x - 1) = 0 \\ x = 1$