Question

calcula los términos d laa siguientes sucesión n| n2+2n-1

Answer 1

Respuesta:es una ecuacio simple.

Explicación paso a paso:

(supongo que querias poner n elevado a 2).

n(n+2n-1), paso a paso seria lo siguiente:  

n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)

=(n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n)(n+2n+−1)

=(n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n)(n)+(n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n)(2n)+(n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n(n+2n−1)n)(−1)

=243n12−405n11+270n10−90n9+15n8−n7+486n12−810n11+540n10−180n9+30n8−2n7−243n11+405n10−270n9+90n8−15n7+n6

=729n12−1458n11+1215n10−540n9+135n8−18n7+n6

Despues de todos los "n" es el numero que sale elevado. OK?