Question

como se desarrolla un problema de log(x+1)/log(x-1)=2

Answer 1

log(x+1)=2log(x-1)
log(x+1)=log(x-1)²
(x+1)=(x-1)²,x+1=(x-1)(x-1)
X+1=x²-x-x+1
X+1=x²-2x+1
-x²+3x=0
X(-x+3)=0
X=0. - x+3=0
X=0. X=3