Question

Given f(x) = (3x - 12) +2, what is the range in set notation?
Suua R >

Answer 1

Answer: The range is (-∞, ∞)

Step by step explanation:

To find the range, we solve for the variable x in terms of y:

    f (x) = (3x - 12) +2

⇒ y = 3x - 10

⇒ 3x - 10 = y

⇒ 3x = y + 10

⇒ x = (y + 10) / 3

So, since y can take any value from the set of real numbers, the range is (-∞, ∞).