Question

10x .elevado a la 4. - 8x elevado a la 3 + 6x .elevado a la 2. -12x + 4
hallar P((1))

Answer 1

$10x^{4} - 8x^3 + 6x^2 - 12x + 4; hallar p(1)$

$p(1) = 10(1)^4 - 8(1)^3 + 6(1)^2 - 12(1) + 4$

$p(1) = 10 - 8 + 6 - 12 + 4$

$p(1) = 20 - 20 ==\ \textgreater \ p(1) = 0$