Question

La masa molecular de una sustancia es 180,7g/mol y su composición centesimal es; C=26,68% H=2,24% O=71,08% halla su fórmula empírica y molecular (Datos C=12, 01 H=1; O=16)

Answer 1

C= 26.68 g / 12 g/mol = 2.223 mol
H = 2.24 g / 1 g/mol  = 2.24 mol
O = 71.08  g / 16 g/mol = 4.443 mol

dividir cada elemento entre el menor de los resultados

C = 2.223 mol / 2.223 mol = 1
H = 2.24 mol / 2.223 mol = 1
O = 4.443 mol / 2.223 mol = 2

FORMULA EMPIRICA = C₁H₁O₂

MASA MOLECULAR DE  LA FE

C = 1 x 12 = 12 g / mol
H = 1 x 1 = 1 g/mol
O = 2 x 16 = 32 g/mol
````````````````````````````````````
         Mm = 45 g/mol

n = 180.7 g/mol
     `````````````````` =  4
       45 g/mol

formula molecular = (FE)n

FM = (C₁H₁O₂)₄  = C₄H₄O₈

Answer 2

Respuesta:

Explicación:

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