La masa molecular de una sustancia es 180,7g/mol y su composición centesimal es; C=26,68% H=2,24% O=71,08% halla su fórmula empírica y molecular (Datos C=12, 01 H=1; O=16)
Respuestas
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C = 26.68 g / 12 g/mol = 2.223 mol
H = 2.24 g / 1 g = 2.24 mol
O = 71.08 g / 16 g = 4.443 mol
dividir entre el menor de los resultados
C = 2.223 mol / 2.223 mol = 1
H = 2.24 mol / 2.223 mol =1
O = 4.443 mol / 2.223 mol = 2
FE = C1H1O2
MASAS MOLECULAR DE LA FE
C = 1 x 12 = 12 g/mol
H = 1 x 1 = 1 g/mol
O = 2 x 16 = 32 g/mol
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Mm = 45 g/mol
n = 180.7 g/mol / 45 g/mol
n = 4
FM = (C1H1O2)4 = C4H4O8
H = 2.24 g / 1 g = 2.24 mol
O = 71.08 g / 16 g = 4.443 mol
dividir entre el menor de los resultados
C = 2.223 mol / 2.223 mol = 1
H = 2.24 mol / 2.223 mol =1
O = 4.443 mol / 2.223 mol = 2
FE = C1H1O2
MASAS MOLECULAR DE LA FE
C = 1 x 12 = 12 g/mol
H = 1 x 1 = 1 g/mol
O = 2 x 16 = 32 g/mol
``````````````````````````````
Mm = 45 g/mol
n = 180.7 g/mol / 45 g/mol
n = 4
FM = (C1H1O2)4 = C4H4O8
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