Question

(-2/3m^2n+3mn^2)-(3/7m^2n+7/5mn^2)-m^2n son numeros fraccionarios no se les ocurra dividir!

Answer 1

$(- \frac{2}{3}m^2n+3mn^2)-( \frac{3}{7}m^2n+ \frac{7}{5}mn^2) -m^2n= \\ \\ Sacamos \ los \ par\'entesis \\ \\ - \frac{2}{3}m^2n+3mn^2- \frac{3}{7}m^2n- \frac{7}{5}mn^2 -m^2n= \qquad \qquad Ordenamos \\ \\ - \frac{2}{3}m^2n- m^2n-\frac{3}{7}m^2n +3mn^2-\frac{7}{5}mn^2 = \\ \\ (- \frac{2}{3}-1-\frac{3}{7})m^2n +(3-\frac{7}{5})mn^2 = \quad \\ \\ Sumamos \ y \ restamos\ los\ coeficientes \\ \\ (- \frac{14}{21}- \frac{21}{21} -\frac{9}{21})m^2n +( \frac{15}{5}-\frac{7}{5})mn^2 =$

$( \frac{-14-21-9}{21})m^2n +( \frac{15-7}{5})mn^2 = \boxed{- \frac{44}{21}m^2n + \frac{8}{5}mn^2}$


Espero que te sirva, salu2!!!!

Answer 2

Respuesta:

no se. .................. .. .