Question

Solucion de la siguientes ecuaciones cuadranticas:
2x^{2} -18=0
3x^{2} -11=0
-x^{2} +12x=0
3x^{2} -9x=0
x^{2} -2x-3=0

Answer 1

Explicación paso a paso:

$2 {x}^{2} - 18 = 0 \\ 2 {x}^{2} = 18 \\ {x}^{2} = \frac{18}{2 } \\ {x}^{2} = 9 \\ x = \sqrt{9} \\ x = 3$

$3 {x}^{2} - 11 = 0 \\ 3 {x}^{2} = 11 \\ {x}^{2} = \frac{11}{3} \\ x = \sqrt{ \frac{11}{3} } \\ \\ \frac{ \sqrt{33} }{3}$

$- {x}^{2} + 12x = 0 \\ {x}^{2} - 12x = 0 \\ (x - 12)(x - 0) \\ (x - 12) = 0 \\ x = 12$

$3 {x}^{2} - 9x = 0 \\ \frac{3 {x}^{2} - 9x = 0 }{3} \\ {x}^{2} - 3x = 0 \\ (x - 3)(x - 0) \\ x - 3 = 0 \\ x= 3$

${x}^{2} - 2x - 3 = 0 \\ (x - 3)(x { + }^{}1) \\ x - 3 = 0 \\ x = 3 \\ x + 1 = 0 \\ x = - 1$

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