Question

2- [3 - 2(x+1)] – 3(2 – x) = 3x+2[x-(3+2x)] + 4(-x -2) ayuda

Answer 1

Explicación paso a paso:

2-[3-2X-2] - 6+3X = 3x+2[x-3-2x] - 4x-8

2-1+2X-6+3X = 3X+2X-6-4X-4X-8

5X - 5= -5X - 14

10X = - 9

X= - 9/10