Question

6)x2 + x - 12 = 0 dos soluciones​

Answer 1

Respuesta:

$x_{1}=3\\x_{2}=-4$

Explicación paso a paso:

$x^{2}+x-12=0\\x=\frac{-b+-\sqrt{b^{2} -4ac} }{2a} \\x=\frac{-1+-\sqrt{1^{2} -4(1)(-12)} }{2(1)}$

$x=\frac{-1+-\sqrt{1+48} }{2}\\\\\x=\frac{-1+-\sqrt{49} }{2} \\\\\\x=\frac{-1+-7 }{2} \\\\\\\\\\x_{1} =3\\x_{2} =-4\sqrt{x}$