Question

me pueden dar la ecuaciones con su procedimiento

$\times {}^{2} - 9 = 0$
$25 \times {}^{2} - 100 = 0$
$64 \times {}^{2} - 128 =0$
$52 m{}^{2} - 225 = 0$
$\times { }^{2} - 49 = 0$
​

Answer 1

Respuesta:

a)$x=3,\:x=-3$

b) $x=2,\:x=-2$

c)$x=\sqrt{2},\:x=-\sqrt{2}$

d) $m=\frac{15\sqrt{13}}{26},\:m=-\frac{15\sqrt{13}}{26}$

e)$x=7,\:x=-7$

Explicación paso a paso:

a)

$x^2-9=0$

$x^2-9+9=0+9$

$\mathrm{Simplificar}\\x^2=9$

$\mathrm{Para\:}x^2=f\left(a\right)\mathrm{\:las\:soluciones\:son\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{9},\:x=-\sqrt{9}$

$x=3,\:x=-3$

b)

$25x^2-100=0$

$25x^2-100+100=0+100$

$25x^2=100$

$\frac{25x^2}{25}=\frac{100}{25}$

$x^2=4$

$x=\sqrt{4},\:x=-\sqrt{4}$}

$x=2,\:x=-2$

c)

$64x^2-128=0$

$64x^2-128+128=0+128$

$64x^2=128$

$\frac{64x^2}{64}=\frac{128}{64}$

$x^2=2$

$x=\sqrt{2},\:x=-\sqrt{2}$

d)

$52m^2-225=0$

$52m^2-225+225=0+225$

$52m^2=225$

$\frac{52m^2}{52}=\frac{225}{52}$

$m=\sqrt{\frac{225}{52}},\:m=-\sqrt{\frac{225}{52}}$

$m=\frac{15\sqrt{13}}{26},\:m=-\frac{15\sqrt{13}}{26}$

e)

$x^2-49=0$

$x^2-49+49=0+49$

$x^2-49+49=0+49$

$x=7,\:x=-7$